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-4w^2-9w+2=0
a = -4; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·(-4)·2
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{113}}{2*-4}=\frac{9-\sqrt{113}}{-8} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{113}}{2*-4}=\frac{9+\sqrt{113}}{-8} $
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